Do it.
Estimate: about , the calculator gives you .
See table.
t | 0 | 1 | 2 | 3 | 4 | 5 | 6 |
log(N) | 1.70 | 1.92 | 2.15 | 2.37 | 2.60 | 2.83 | 3.05 |
Yes, you get a straight line that goes through and . Since the graph of is approximated by a straight line, then must be an exponential function (roughly).
For the following is true: and .
This results in: and , and therefore . A suitable formula is .
gives you and therefore .
gives you and therefore .
The tick labels on both axes are powers of .
and .
through and .
This results in and , so .
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