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Exercises

Exercise 1

Here you see a truncated cube with edges of 6 cm. The points P , Q and R are the centers of the edges they are situated on.

a

Draw a "parallel" projection of this truncated cube with an angle of 30 ° and a scaling factor of 0,5 .

b

Make a life-size drawing of ΔPQR at full scale.

c

The diagonal surface D B Q S H is a pentagon. Make a life-size drawing of this diagonal surface of the truncated cube.

Exercise 2

Given is a regular pyramid T . A B C D with the square A B C D as the base. The edges of A B C D are 6 cm and the height T S of the pyramid is 10 cm. S is the intersection point of A C and B D .

a

Draw a "parallel" projection of this pyramid on a grid.

b

Divide all edges into three equal parts. Explain what you do.

c

Connect the points in the base so that you get an octagon.

d

Is this octagon the base of a regular octagonal pyramid? Explain.

Exercise 3

When you connect the centers of the sides of a cube, you get an octahedron (regular eightsided polyhedron) A B C D E F . In this octahedron A C = B D = E F = 8 cm.

a

Draw a parallel projection of this octahedron.

b

What shape do all sides of the octahedron have? Draw one of them full size.

c

What solid has vertices that are the centers of the sides of the octahedron?

Exercise 4

Here you see a so called hipped roof, a roof with a rectangular base A B C D with the roof-ridge E F situated exactly over the middle of the base. The roof itself consists of twee equilateral triangles and two symmetric trapeziums.

a

Draw a parallel projection of this roof in a grid with scale 1 : 100 .

b

The roof itself consists of two isosceles triangles and two symmetric trapeziums. Use measurements in a suitable plane to determine the height of those two isosceles triangles. give your answer in whole dm. Draw one of those triangles on a scale of 1:100.

c

Determine the height of the two trapeziums by measuring in a suitable figure. Give the height in whole dm and draw one trapezium with scale 1:100.

Exercise 5

Beside you see a photo of the building "Willemswerf" in Rotterdam and below you see a view from above of a very simplified version of the building. This strongly simplified version has a height of 80 m. The bend in the building starts 10 m above the ground.

a

Draw your own parallel projection of the simplified version of the building "Willemswerf" in a grid with scale 1 : 100 .

b

The bend in the building is trapezium shaped. Make a scaled drawing of that plane with scale 1 : 100 .

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